(请作答此空)的目的是检查模块之间，以及模块和已集成的软件之间的接口关系，并验证已集成的软件是否符合设计要求。其测试的技术依据是()。
A.单元测试
B.集成测试
C.系统测试
D.回归测试

根据《计算机软件保护条例》,下列说法中,错误的是()
A.受保护的软件必须固化在有形物体上,如硬盘、光盘、软盘等
B.含法复割品所有人的权利包括出于学习研究目的,安装、储存、显示等方式使用复制品,必须经著作权人许可可不向其变付报酬
C.如果开发者在单位或组织中任职期间,所开发的软件符含一定条件,则软件著作权应归单位或组织所有
D.接受他人委托而进行开发的软件,其著作权的归属应由委托人与受托人签订书面合同的定;如果没有签订含同或合同中未规定的,则其著作权由受托人享有

在系统开发中，原型可以划分为不同的种类。从原型是否实现功能来分，可以分为水平原型和垂直原型；从原型最终结果来分，可以分为抛弃式原型和演化式原型。以下关于原型的叙述中，正确的是（30）。
A.水平原型适合于算法较为复杂的项目
B.垂直原型适合于Web项目
C.抛弃式原型适合于需求不确定、不完整、含糊不清的项目
D.演化式原型主要用于界面设计

The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.All the documents of the project need to be part of this （　）. This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(备忘录).Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first （请作答此空） proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project （ ） ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.The second reason for the project workbook is control of the distribution of （ ）. The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The （ ） allows distribution lists to be maintained by subtree, if that is desirable.
A. OBJECTIVE
B. MEMORANDA
C. STANDARD
D. SPECIFICATION

以下关于系统性能评估方法的描述，错误的是____。
A.指令执行速度法常用每秒百万次指令运算（MIPS）评估系统性能
B.基准程序法主要针对CPU（有时包括主存）的性能，但没有考虑I/O结构、操作系统、编译程序的效率等对系统性能的影响
C.等效指令速度法评估系统性能时需要计算各类指令在程序中所占的比例
D.综合理论性能法（CPT）采用每秒百万次理论运算（MTOPS）评估系统性能

循环冗余校验码（Cyc1icRedundancyCheck，CRC)是数据通信领域中最常用的一种差错校验码，该校验方法中，使用多项式除法（模2除法）运算后的余数为校验字段。若数据信息为n位，则将其左移k位后，被长度为k+1位的生成多项式相除，所得的k位余数即构成k个校验位，构成n+k位编码。若数据信息为1100，生成多项式为X3+X+l(即1011)，则CRC编码是（14）。
A.1100010
B.1011010
C.1100011
D.1011110